# Time and Distance Multiple Choice Questions

## Time and Distance

Question 1.

A car covers its journey at the speed of 80km/hr in 10hours. If the same distance is to be covered in 4 hours, by how much the speed of car will have to increase ?

 A. 40km/hr B. 60km/hr C. 90km/hr D. 120km/hr
Explanation :

Initial speed = 80km/hr
Total distance = 80 * 10 = 800km
new speed = 800/4 =200km/hr
Increase in speed = 200 - 80 = 120km/hr

Question 2.

two cars A and B are running in the same direction. Car A has already covered a distance of 60kms when car B started running. The cars meet each other in 3 hours after car B started running. What was

 A. 20km/hr B. 30km/hr C. 15km/hr D. None of these
Explanation :

Difference between speeds of car A and car B = 60/3 = 20km/hr
But from the result it is impossible to find the speed of car A because here the unkowns are two (Speeds of cars A and B ) but the equation is only one

Question 3.

Walking 3/4th of his usual rate, a man is 15min late. Find his usual time in minutes

 A. 30 B. 35 C. 45 D. 25
Explanation :

Walking at 3/4th of usual rate implies that time taken would be 4/3th of the usual time. In other words, the time taken is 1/3rd more than his usual time
so 1/3rd of the usual time = 15min
or usual time = 3 * 15 = 45min

Question 4.

A monkey climbs up a greased pole, ascends 20m and slip 4m in alternate minutes. If the pole is 96m high, how many minutes will it take to reach the top?

 A. 54/5 B. 12 C. 44/5 D. 9
Explanation :

net height climbed in 2 min = 20m - 4m = 16m
In 10 min the net height climbed = 16 * 10/2 = 80m
Remaining height = 96m - 80m = 16m
In the 11th min , the monkey will be ascending up.
Time taken to ascend the last 16min
16/20 = 4/5min
Total time taken = 10 + 4/5 = 54/5 min

Question 5.

A car is running at 7/10 of its own speed reached a place in 22 hours. How much time could be saved if the train would run at its own speed ?

 A. 4hours B. 6hours C. 7hours D. 8hours
Explanation :

Since the car runs at 7/11 th of its own speed, the time it take is 11/7th of its usual speed.
let the usual time taken be t hours
then we can write, 11t / 7 = 22
or t  = 22 * 7 / 11 = 14 hours
Time saved  = 22 - 14 = 8hours